P^2-6p+3=-4p^2

Solution for P^2-6p+3=-4p^2 equation:

^2-6P+3=-4P^2

We move all terms to the left:

^2-6P+3-(-4P^2)=0

We add all the numbers together, and all the variables

-(-4P^2)-6P=0

We get rid of parentheses

4P^2-6P=0

a = 4; b = -6; c = 0;
Δ = b2-4ac
Δ = -62-4·4·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6}{2*4}=\frac{0}{8}
=0
$
$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6}{2*4}=\frac{12}{8}
=1+1/2
$